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3x+5=2(x-1)+(x-1)
We move all terms to the left:
3x+5-(2(x-1)+(x-1))=0
We calculate terms in parentheses: -(2(x-1)+(x-1)), so:We get rid of parentheses
2(x-1)+(x-1)
We multiply parentheses
2x+(x-1)-2
We get rid of parentheses
2x+x-1-2
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
3x-3x+3+5=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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