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3x+5=5+(x-3)
We move all terms to the left:
3x+5-(5+(x-3))=0
We calculate terms in parentheses: -(5+(x-3)), so:We get rid of parentheses
5+(x-3)
determiningTheFunctionDomain (x-3)+5
We get rid of parentheses
x-3+5
We add all the numbers together, and all the variables
x+2
Back to the equation:
-(x+2)
3x-x-2+5=0
We add all the numbers together, and all the variables
2x+3=0
We move all terms containing x to the left, all other terms to the right
2x=-3
x=-3/2
x=-1+1/2
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