3x+5x+20+18=2(2x+4x+5x+5)

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Solution for 3x+5x+20+18=2(2x+4x+5x+5) equation: 



3x+5x+20+18=2(2x+4x+5x+5)

We move all terms to the left:

3x+5x+20+18-(2(2x+4x+5x+5))=0

We add all the numbers together, and all the variables

3x+5x-(2(11x+5))+20+18=0

We add all the numbers together, and all the variables

8x-(2(11x+5))+38=0



We calculate terms in parentheses: -(2(11x+5)), so:

2(11x+5)

We multiply parentheses

22x+10

Back to the equation:

-(22x+10)



We get rid of parentheses

8x-22x-10+38=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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