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3x+5x+4x=2(x+2)+2(x+2)
We move all terms to the left:
3x+5x+4x-(2(x+2)+2(x+2))=0
We add all the numbers together, and all the variables
12x-(2(x+2)+2(x+2))=0
We calculate terms in parentheses: -(2(x+2)+2(x+2)), so:We get rid of parentheses
2(x+2)+2(x+2)
We multiply parentheses
2x+2x+4+4
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
12x-4x-8=0
We add all the numbers together, and all the variables
8x-8=0
We move all terms containing x to the left, all other terms to the right
8x=8
x=8/8
x=1
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