3x+65=-(7/5)x-145

Solution for 3x+65=-(7/5)x-145 equation:

3x+65=-(7/5)x-145

We move all terms to the left:

3x+65-(-(7/5)x-145)=0


Domain of the equation: 5)x-145)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x-(-(+7/5)x-145)+65=0

We multiply all the terms by the denominator


3x*5)x-145)-(-(+65*5)x-145)+7=0

We add all the numbers together, and all the variables

3x*5)x-145)-(-325x-145)+7=0

Wy multiply elements

15x^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$