3x+6=(3x+6)(3x+6)

Solution for 3x+6=(3x+6)(3x+6) equation:

3x+6=(3x+6)(3x+6)

We move all terms to the left:

3x+6-((3x+6)(3x+6))=0

We multiply parentheses ..

-((+9x^2+18x+18x+36))+3x+6=0


We calculate terms in parentheses: -((+9x^2+18x+18x+36)), so:

(+9x^2+18x+18x+36)

We get rid of parentheses

9x^2+18x+18x+36

We add all the numbers together, and all the variables

9x^2+36x+36

Back to the equation:

-(9x^2+36x+36)


We add all the numbers together, and all the variables

3x-(9x^2+36x+36)+6=0

We get rid of parentheses

-9x^2+3x-36x-36+6=0

We add all the numbers together, and all the variables

-9x^2-33x-30=0

a = -9; b = -33; c = -30;
Δ = b2-4ac
Δ = -332-4·(-9)·(-30)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3}{2*-9}=\frac{30}{-18}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3}{2*-9}=\frac{36}{-18}
=-2
$