3x+6=(9x-3)/9

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Solution for 3x+6=(9x-3)/9 equation: 



3x+6=(9x-3)/9

We move all terms to the left:

3x+6-((9x-3)/9)=0

We multiply all the terms by the denominator


3x*9)-((9x-3)+6*9)=0

We add all the numbers together, and all the variables

3x*9)-((9x-3)=0

Wy multiply elements

27x^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{54}=0$

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