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3x+6=6(x+3)+-3x
We move all terms to the left:
3x+6-(6(x+3)+-3x)=0
We use the square of the difference formula
3x-(6(x+3)-3x)+6=0
We calculate terms in parentheses: -(6(x+3)-3x), so:We get rid of parentheses
6(x+3)-3x
We add all the numbers together, and all the variables
-3x+6(x+3)
We multiply parentheses
-3x+6x+18
We add all the numbers together, and all the variables
3x+18
Back to the equation:
-(3x+18)
3x-3x-18+6=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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