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3x+6=x2+26
We move all terms to the left:
3x+6-(x2+26)=0
We add all the numbers together, and all the variables
-(+x^2+26)+3x+6=0
We get rid of parentheses
-x^2+3x-26+6=0
We add all the numbers together, and all the variables
-1x^2+3x-20=0
a = -1; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·(-1)·(-20)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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