3x+6x+3x-195=128112x-195=128112x=1476-x=123.

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Solution for 3x+6x+3x-195=128112x-195=128112x=1476-x=123. equation: 



3x+6x+3x-195=128112x-195=128112x=1476-x=123.

We move all terms to the left:

3x+6x+3x-195-(128112x-195)=0

We add all the numbers together, and all the variables

12x-(128112x-195)-195=0

We get rid of parentheses

12x-128112x+195-195=0

We add all the numbers together, and all the variables

-128100x=0

x=0/-128100

x=0

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