3x+6x-4=4(x+19)

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Solution for 3x+6x-4=4(x+19) equation: 



3x+6x-4=4(x+19)

We move all terms to the left:

3x+6x-4-(4(x+19))=0

We add all the numbers together, and all the variables

9x-(4(x+19))-4=0



We calculate terms in parentheses: -(4(x+19)), so:

4(x+19)

We multiply parentheses

4x+76

Back to the equation:

-(4x+76)



We get rid of parentheses

9x-4x-76-4=0

We add all the numbers together, and all the variables

5x-80=0

We move all terms containing x to the left, all other terms to the right

5x=80

x=80/5

x=16

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