3x+6x=4x-(3x-40)

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Solution for 3x+6x=4x-(3x-40) equation: 



3x+6x=4x-(3x-40)

We move all terms to the left:

3x+6x-(4x-(3x-40))=0

We add all the numbers together, and all the variables

9x-(4x-(3x-40))=0



We calculate terms in parentheses: -(4x-(3x-40)), so:

4x-(3x-40)

We get rid of parentheses

4x-3x+40

We add all the numbers together, and all the variables

x+40

Back to the equation:

-(x+40)



We get rid of parentheses

9x-x-40=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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