3x+7-5=2(x+1)+x

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Solution for 3x+7-5=2(x+1)+x equation: 



3x+7-5=2(x+1)+x

We move all terms to the left:

3x+7-5-(2(x+1)+x)=0

We add all the numbers together, and all the variables

3x-(2(x+1)+x)+2=0



We calculate terms in parentheses: -(2(x+1)+x), so:

2(x+1)+x

We add all the numbers together, and all the variables

x+2(x+1)

We multiply parentheses

x+2x+2

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

3x-3x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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