3x+7-x+8=3(2x+1)

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Solution for 3x+7-x+8=3(2x+1) equation: 



3x+7-x+8=3(2x+1)

We move all terms to the left:

3x+7-x+8-(3(2x+1))=0

We add all the numbers together, and all the variables

2x-(3(2x+1))+15=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

2x-6x-3+15=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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