3x+7-x+8=3(2x+1)

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Solution for 3x+7-x+8=3(2x+1) equation:



3x+7-x+8=3(2x+1)
We move all terms to the left:
3x+7-x+8-(3(2x+1))=0
We add all the numbers together, and all the variables
2x-(3(2x+1))+15=0
We calculate terms in parentheses: -(3(2x+1)), so:
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
We get rid of parentheses
2x-6x-3+15=0
We add all the numbers together, and all the variables
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3

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