3x+7=14x-15+4(x-2)=10(x+1)+5x-2(x+3)=x+6

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Solution for 3x+7=14x-15+4(x-2)=10(x+1)+5x-2(x+3)=x+6 equation: 



3x+7=14x-15+4(x-2)=10(x+1)+5x-2(x+3)=x+6

We move all terms to the left:

3x+7-(14x-15+4(x-2))=0



We calculate terms in parentheses: -(14x-15+4(x-2)), so:

14x-15+4(x-2)

determiningTheFunctionDomain
14x+4(x-2)-15

We multiply parentheses

14x+4x-8-15

We add all the numbers together, and all the variables

18x-23

Back to the equation:

-(18x-23)



We get rid of parentheses

3x-18x+23+7=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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