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3x+7=2x+-3(x-4)
We move all terms to the left:
3x+7-(2x+-3(x-4))=0
We use the square of the difference formula
3x-(2x-3(x-4))+7=0
We calculate terms in parentheses: -(2x-3(x-4)), so:We get rid of parentheses
2x-3(x-4)
We multiply parentheses
2x-3x+12
We add all the numbers together, and all the variables
-1x+12
Back to the equation:
-(-1x+12)
3x+1x-12+7=0
We add all the numbers together, and all the variables
4x-5=0
We move all terms containing x to the left, all other terms to the right
4x=5
x=5/4
x=1+1/4
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