3x+7x+1=1/2(20x+4)+2

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Solution for 3x+7x+1=1/2(20x+4)+2 equation: 



3x+7x+1=1/2(20x+4)+2

We move all terms to the left:

3x+7x+1-(1/2(20x+4)+2)=0



Domain of the equation: 2(20x+4)+2)!=0

x∈R



We add all the numbers together, and all the variables

10x-(1/2(20x+4)+2)+1=0

We multiply all the terms by the denominator


10x*2(20x+4)+1*2(20x+4)+2)-(1+2)=0

We add all the numbers together, and all the variables

10x*2(20x+4)+1*2(20x+4)+2)-3=0

We add all the numbers together, and all the variables

10x*2(20x+4)+1*2(20x+4)=0

Wy multiply elements

20x^2(2+2x(2=0

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