3x+7x+1=2(5x+1)/2

Solution for 3x+7x+1=2(5x+1)/2 equation:

3x+7x+1=2(5x+1)/2

We move all terms to the left:

3x+7x+1-(2(5x+1)/2)=0

We add all the numbers together, and all the variables

10x-(2(5x+1)/2)+1=0

We multiply all the terms by the denominator


10x*2)-(2(5x+1)+1*2)=0

We add all the numbers together, and all the variables

10x*2)-(2(5x+1)=0

Wy multiply elements

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$