3x+7x-11-2x=4(x-6)-19

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Solution for 3x+7x-11-2x=4(x-6)-19 equation: 



3x+7x-11-2x=4(x-6)-19

We move all terms to the left:

3x+7x-11-2x-(4(x-6)-19)=0

We add all the numbers together, and all the variables

8x-(4(x-6)-19)-11=0



We calculate terms in parentheses: -(4(x-6)-19), so:

4(x-6)-19

We multiply parentheses

4x-24-19

We add all the numbers together, and all the variables

4x-43

Back to the equation:

-(4x-43)



We get rid of parentheses

8x-4x+43-11=0

We add all the numbers together, and all the variables

4x+32=0

We move all terms containing x to the left, all other terms to the right

4x=-32

x=-32/4

x=-8

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