3x+8+2/3x+40=2x+48

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Solution for 3x+8+2/3x+40=2x+48 equation:



3x+8+2/3x+40=2x+48
We move all terms to the left:
3x+8+2/3x+40-(2x+48)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
3x+2/3x-(2x+48)+48=0
We get rid of parentheses
3x+2/3x-2x-48+48=0
We multiply all the terms by the denominator
3x*3x-2x*3x-48*3x+48*3x+2=0
Wy multiply elements
9x^2-6x^2-144x+144x+2=0
We add all the numbers together, and all the variables
3x^2+2=0
a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation

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