3x+8+4x=-8(x-6)+8(13x+5)

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Solution for 3x+8+4x=-8(x-6)+8(13x+5) equation: 



3x+8+4x=-8(x-6)+8(13x+5)

We move all terms to the left:

3x+8+4x-(-8(x-6)+8(13x+5))=0

We add all the numbers together, and all the variables

7x-(-8(x-6)+8(13x+5))+8=0



We calculate terms in parentheses: -(-8(x-6)+8(13x+5)), so:

-8(x-6)+8(13x+5)

We multiply parentheses

-8x+104x+48+40

We add all the numbers together, and all the variables

96x+88

Back to the equation:

-(96x+88)



We get rid of parentheses

7x-96x-88+8=0

We add all the numbers together, and all the variables

-89x-80=0

We move all terms containing x to the left, all other terms to the right

-89x=80

x=80/-89

x=-80/89

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