3x+8+4x=-8(x-6)-8(13x+15)

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Solution for 3x+8+4x=-8(x-6)-8(13x+15) equation: 



3x+8+4x=-8(x-6)-8(13x+15)

We move all terms to the left:

3x+8+4x-(-8(x-6)-8(13x+15))=0

We add all the numbers together, and all the variables

7x-(-8(x-6)-8(13x+15))+8=0



We calculate terms in parentheses: -(-8(x-6)-8(13x+15)), so:

-8(x-6)-8(13x+15)

We multiply parentheses

-8x-104x+48-120

We add all the numbers together, and all the variables

-112x-72

Back to the equation:

-(-112x-72)



We get rid of parentheses

7x+112x+72+8=0

We add all the numbers together, and all the variables

119x+80=0

We move all terms containing x to the left, all other terms to the right

119x=-80

x=-80/119

x=-80/119

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