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3x+8-5x=(16-6x)/2
We move all terms to the left:
3x+8-5x-((16-6x)/2)=0
We add all the numbers together, and all the variables
3x-5x-((-6x+16)/2)+8=0
We add all the numbers together, and all the variables
-2x-((-6x+16)/2)+8=0
We multiply all the terms by the denominator
-2x*2)-((-6x+16)+8*2)=0
We add all the numbers together, and all the variables
-2x*2)-((-6x+16)=0
Wy multiply elements
-4x^2=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-8}=0$
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