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3x+8/7x-6=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
3x*7x-6*7x+8=0
Wy multiply elements
21x^2-42x+8=0
a = 21; b = -42; c = +8;
Δ = b2-4ac
Δ = -422-4·21·8
Δ = 1092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1092}=\sqrt{4*273}=\sqrt{4}*\sqrt{273}=2\sqrt{273}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{273}}{2*21}=\frac{42-2\sqrt{273}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{273}}{2*21}=\frac{42+2\sqrt{273}}{42} $
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