3x+8/x-4=7

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Solution for 3x+8/x-4=7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+8/x-4 = 7 // - 7

3*x+8/x-7-4 = 0

3*x^1+8*x^-1-11*x^0 = 0

(3*x^2-11*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-11*x^1+8*x^0) = 0

x^1

3*x^2-11*x+8 = 0

3*x^2-11*x+8 = 0

DELTA = (-11)^2-(3*4*8)

DELTA = 25

DELTA > 0

x = (25^(1/2)+11)/(2*3) or x = (11-25^(1/2))/(2*3)

x = 8/3 or x = 1

x in { 1, 8/3} 

x in { 1, 8/3 }

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