3x+8=(2x+1)+10

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Solution for 3x+8=(2x+1)+10 equation:



3x+8=(2x+1)+10
We move all terms to the left:
3x+8-((2x+1)+10)=0
We calculate terms in parentheses: -((2x+1)+10), so:
(2x+1)+10
We get rid of parentheses
2x+1+10
We add all the numbers together, and all the variables
2x+11
Back to the equation:
-(2x+11)
We get rid of parentheses
3x-2x-11+8=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3

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