3x+8=(2x+1)+10

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Solution for 3x+8=(2x+1)+10 equation: 



3x+8=(2x+1)+10

We move all terms to the left:

3x+8-((2x+1)+10)=0



We calculate terms in parentheses: -((2x+1)+10), so:

(2x+1)+10

We get rid of parentheses

2x+1+10

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

3x-2x-11+8=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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