3x+8=2x-4-3(x-1)

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Solution for 3x+8=2x-4-3(x-1) equation: 



3x+8=2x-4-3(x-1)

We move all terms to the left:

3x+8-(2x-4-3(x-1))=0



We calculate terms in parentheses: -(2x-4-3(x-1)), so:

2x-4-3(x-1)

determiningTheFunctionDomain
2x-3(x-1)-4

We multiply parentheses

2x-3x+3-4

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

-(-1x-1)



We get rid of parentheses

3x+1x+1+8=0

We add all the numbers together, and all the variables

4x+9=0

We move all terms containing x to the left, all other terms to the right

4x=-9

x=-9/4

x=-2+1/4

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