3x+8=7(x+1)-19

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Solution for 3x+8=7(x+1)-19 equation: 



3x+8=7(x+1)-19

We move all terms to the left:

3x+8-(7(x+1)-19)=0



We calculate terms in parentheses: -(7(x+1)-19), so:

7(x+1)-19

We multiply parentheses

7x+7-19

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We get rid of parentheses

3x-7x+12+8=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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