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3x+9(x-2)=4(3x-3)-6
We move all terms to the left:
3x+9(x-2)-(4(3x-3)-6)=0
We multiply parentheses
3x+9x-(4(3x-3)-6)-18=0
We calculate terms in parentheses: -(4(3x-3)-6), so:We add all the numbers together, and all the variables
4(3x-3)-6
We multiply parentheses
12x-12-6
We add all the numbers together, and all the variables
12x-18
Back to the equation:
-(12x-18)
12x-(12x-18)-18=0
We get rid of parentheses
12x-12x+18-18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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