3x+9=(2x-5)+20

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Solution for 3x+9=(2x-5)+20 equation: 



3x+9=(2x-5)+20

We move all terms to the left:

3x+9-((2x-5)+20)=0



We calculate terms in parentheses: -((2x-5)+20), so:

(2x-5)+20

We get rid of parentheses

2x-5+20

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We get rid of parentheses

3x-2x-15+9=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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