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3x+9=-3x(x-3)
We move all terms to the left:
3x+9-(-3x(x-3))=0
We calculate terms in parentheses: -(-3x(x-3)), so:We get rid of parentheses
-3x(x-3)
We multiply parentheses
-3x^2+9x
Back to the equation:
-(-3x^2+9x)
3x^2-9x+3x+9=0
We add all the numbers together, and all the variables
3x^2-6x+9=0
a = 3; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·3·9
Δ = -72
Delta is less than zero, so there is no solution for the equation
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