3x+x(x-2)+58+12=10

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Solution for 3x+x(x-2)+58+12=10 equation: 



3x+x(x-2)+58+12=10

We move all terms to the left:

3x+x(x-2)+58+12-(10)=0

We add all the numbers together, and all the variables

3x+x(x-2)+60=0

We multiply parentheses

x^2+3x-2x+60=0

We add all the numbers together, and all the variables

x^2+x+60=0

a = 1; b = 1; c = +60;
Δ = b2-4ac
Δ = 12-4·1·60
Δ = -239
Delta is less than zero, so there is no solution for the equation

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