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3x+x+3=4(x+1)
We move all terms to the left:
3x+x+3-(4(x+1))=0
We add all the numbers together, and all the variables
4x-(4(x+1))+3=0
We calculate terms in parentheses: -(4(x+1)), so:We get rid of parentheses
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
4x-4x-4+3=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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