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3x+x-3=4(x+3)-15
We move all terms to the left:
3x+x-3-(4(x+3)-15)=0
We add all the numbers together, and all the variables
4x-(4(x+3)-15)-3=0
We calculate terms in parentheses: -(4(x+3)-15), so:We get rid of parentheses
4(x+3)-15
We multiply parentheses
4x+12-15
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
4x-4x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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