3x+x2-208=0

Solution for 3x+x2-208=0 equation:

3x+x2-208=0

We add all the numbers together, and all the variables

x^2+3x-208=0

a = 1; b = 3; c = -208;
Δ = b2-4ac
Δ = 32-4·1·(-208)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-29}{2*1}=\frac{-32}{2}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+29}{2*1}=\frac{26}{2}
=13
$