3x+y+4z+114=2

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Solution for 3x+y+4z+114=2 equation:


Simplifying
3x + y + 4z + 114 = 2

Reorder the terms:
114 + 3x + y + 4z = 2

Solving
114 + 3x + y + 4z = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-114' to each side of the equation.
114 + 3x + y + -114 + 4z = 2 + -114

Reorder the terms:
114 + -114 + 3x + y + 4z = 2 + -114

Combine like terms: 114 + -114 = 0
0 + 3x + y + 4z = 2 + -114
3x + y + 4z = 2 + -114

Combine like terms: 2 + -114 = -112
3x + y + 4z = -112

Add '-1y' to each side of the equation.
3x + y + -1y + 4z = -112 + -1y

Combine like terms: y + -1y = 0
3x + 0 + 4z = -112 + -1y
3x + 4z = -112 + -1y

Add '-4z' to each side of the equation.
3x + 4z + -4z = -112 + -1y + -4z

Combine like terms: 4z + -4z = 0
3x + 0 = -112 + -1y + -4z
3x = -112 + -1y + -4z

Divide each side by '3'.
x = -37.33333333 + -0.3333333333y + -1.333333333z

Simplifying
x = -37.33333333 + -0.3333333333y + -1.333333333z

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