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3x-(-2-4x)*x=5
We move all terms to the left:
3x-(-2-4x)*x-(5)=0
We add all the numbers together, and all the variables
3x-(-4x-2)*x-5=0
We multiply parentheses
4x^2+3x+2x-5=0
We add all the numbers together, and all the variables
4x^2+5x-5=0
a = 4; b = 5; c = -5;
Δ = b2-4ac
Δ = 52-4·4·(-5)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{105}}{2*4}=\frac{-5-\sqrt{105}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{105}}{2*4}=\frac{-5+\sqrt{105}}{8} $
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