3x-(-2x+16)=4(x-4)+x

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Solution for 3x-(-2x+16)=4(x-4)+x equation: 



3x-(-2x+16)=4(x-4)+x

We move all terms to the left:

3x-(-2x+16)-(4(x-4)+x)=0

We get rid of parentheses

3x+2x-(4(x-4)+x)-16=0



We calculate terms in parentheses: -(4(x-4)+x), so:

4(x-4)+x

We add all the numbers together, and all the variables

x+4(x-4)

We multiply parentheses

x+4x-16

We add all the numbers together, and all the variables

5x-16

Back to the equation:

-(5x-16)



We add all the numbers together, and all the variables

5x-(5x-16)-16=0

We get rid of parentheses

5x-5x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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