3x-(-3)-8=10+4x

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Solution for 3x-(-3)-8=10+4x equation: 



3x-(-3)-8=10+4x

We move all terms to the left:

3x-(-3)-8-(10+4x)=0

We add all the numbers together, and all the variables

3x-(4x+10)-8-(-3)=0

We add all the numbers together, and all the variables

3x-(4x+10)-5=0

We get rid of parentheses

3x-4x-10-5=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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