3x-(-x)+2(-x)=2(-x)+(-16)

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Solution for 3x-(-x)+2(-x)=2(-x)+(-16) equation: 



3x-(-x)+2(-x)=2(-x)+(-16)

We move all terms to the left:

3x-(-x)+2(-x)-(2(-x)+(-16))=0

We add all the numbers together, and all the variables

3x-(-1x)+2(-1x)-(2(-1x)+(-16))=0

We multiply parentheses

3x-(-1x)-2x-(2(-1x)+(-16))=0

We get rid of parentheses

3x+1x-2x-(2(-1x)+(-16))=0



We calculate terms in parentheses: -(2(-1x)+(-16)), so:

2(-1x)+(-16)

We add all the numbers together, and all the variables

2(-1x)-16

We multiply parentheses

-2x-16

Back to the equation:

-(-2x-16)



We add all the numbers together, and all the variables

2x-(-2x-16)=0

We get rid of parentheses

2x+2x+16=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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