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3x-(1/2)(10x+6)=15
We move all terms to the left:
3x-(1/2)(10x+6)-(15)=0
Domain of the equation: 2)(10x+6)!=0We add all the numbers together, and all the variables
x∈R
3x-(+1/2)(10x+6)-15=0
We multiply parentheses ..
-(+10x^2+1/2*6)+3x-15=0
We multiply all the terms by the denominator
-(+10x^2+1+3x*2*6)-15*2*6)=0
We add all the numbers together, and all the variables
-(+10x^2+1+3x*2*6)=0
We get rid of parentheses
-10x^2-3x*2*6-1=0
Wy multiply elements
-10x^2-36x*6-1=0
Wy multiply elements
-10x^2-216x-1=0
a = -10; b = -216; c = -1;
Δ = b2-4ac
Δ = -2162-4·(-10)·(-1)
Δ = 46616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46616}=\sqrt{4*11654}=\sqrt{4}*\sqrt{11654}=2\sqrt{11654}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-2\sqrt{11654}}{2*-10}=\frac{216-2\sqrt{11654}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+2\sqrt{11654}}{2*-10}=\frac{216+2\sqrt{11654}}{-20} $
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