3x-(1/2)*((x/5)+6)=25+(3x/2)

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Solution for 3x-(1/2)*((x/5)+6)=25+(3x/2) equation: 


x in (-oo:+oo)

3*x-((1/2)*(x/5+6)) = (3*x)/2+25 // - (3*x)/2+25

3*x-((1/2)*(x/5+6))-((3*x)/2)-25 = 0

(-1/2)*(x/5+6)+3*x+(-3/2)*x-25 = 0

3*x-1/2*(1/5*x+6)+(-3*x)/2-25 = 0

(-1/2*2*(1/5*x+6))/2+(2*3*x)/2+(-3*x)/2+(-25*2)/2 = 0

2*3*x-1/2*2*(1/5*x+6)-3*x-25*2 = 0

29/5*x-3*x-50-6 = 0

14/5*x-50-6 = 0

14/5*x-56 = 0

(14/5*x-56)/2 = 0

(14/5*x-56)/2 = 0 // * 2

14/5*x-56 = 0

14/5*x-56 = 0 // + 56

14/5*x = 56 // : 14/5

x = 56/14/5

x = 20

x = 20

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