3x-(16-4x)=12

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Solution for 3x-(16-4x)=12 equation: 



3x-(16-4x)=12

We move all terms to the left:

3x-(16-4x)-(12)=0

We add all the numbers together, and all the variables

3x-(-4x+16)-12=0

We get rid of parentheses

3x+4x-16-12=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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