3x-(20-4x)/2

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Solution for 3x-(20-4x)/2 equation: 


x in (-oo:+oo)

3*x-((20-(4*x))/2) = 0

3*x-((20-4*x)/2) = 0

(-1*(20-4*x))/2+3*x = 0

(-1*(20-4*x))/2+(2*3*x)/2 = 0

2*3*x-1*(20-4*x) = 0

10*x-20 = 0

(10*x-20)/2 = 0

(10*x-20)/2 = 0 // * 2

10*x-20 = 0

10*x-20 = 0 // + 20

10*x = 20 // : 10

x = 20/10

x = 2

x = 2

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