3x-(2x+6)=-3x(-4x+6)

Solution for 3x-(2x+6)=-3x(-4x+6) equation:

3x-(2x+6)=-3x(-4x+6)

We move all terms to the left:

3x-(2x+6)-(-3x(-4x+6))=0

We get rid of parentheses

3x-2x-(-3x(-4x+6))-6=0


We calculate terms in parentheses: -(-3x(-4x+6)), so:

-3x(-4x+6)

We multiply parentheses

12x^2-18x

Back to the equation:

-(12x^2-18x)


We add all the numbers together, and all the variables

x-(12x^2-18x)-6=0

We get rid of parentheses

-12x^2+x+18x-6=0

We add all the numbers together, and all the variables

-12x^2+19x-6=0

a = -12; b = 19; c = -6;
Δ = b2-4ac
Δ = 192-4·(-12)·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{73}}{2*-12}=\frac{-19-\sqrt{73}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{73}}{2*-12}=\frac{-19+\sqrt{73}}{-24}
$