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3x-(2x-6)=3(x-4)
We move all terms to the left:
3x-(2x-6)-(3(x-4))=0
We get rid of parentheses
3x-2x-(3(x-4))+6=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
x-(3x-12)+6=0
We get rid of parentheses
x-3x+12+6=0
We add all the numbers together, and all the variables
-2x+18=0
We move all terms containing x to the left, all other terms to the right
-2x=-18
x=-18/-2
x=+9
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