3x-(2x/3-5)=6-(x/3-2)

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Solution for 3x-(2x/3-5)=6-(x/3-2) equation: 



3x-(2x/3-5)=6-(x/3-2)

We move all terms to the left:

3x-(2x/3-5)-(6-(x/3-2))=0

We get rid of parentheses

3x-2x/3-(6-(x/3-2))+5=0

We calculate fractions


3x+5=0

We move all terms containing x to the left, all other terms to the right

3x=-5

x=-5/3

x=-1+2/3

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