3x-(3-3y)+3(z+1)=

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Solution for 3x-(3-3y)+3(z+1)= equation:


Simplifying
3x + -1(3 + -3y) + 3(z + 1) = 0
3x + (3 * -1 + -3y * -1) + 3(z + 1) = 0
3x + (-3 + 3y) + 3(z + 1) = 0

Reorder the terms:
3x + -3 + 3y + 3(1 + z) = 0
3x + -3 + 3y + (1 * 3 + z * 3) = 0
3x + -3 + 3y + (3 + 3z) = 0

Reorder the terms:
-3 + 3 + 3x + 3y + 3z = 0

Combine like terms: -3 + 3 = 0
0 + 3x + 3y + 3z = 0
3x + 3y + 3z = 0

Solving
3x + 3y + 3z = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y' to each side of the equation.
3x + 3y + -3y + 3z = 0 + -3y

Combine like terms: 3y + -3y = 0
3x + 0 + 3z = 0 + -3y
3x + 3z = 0 + -3y
Remove the zero:
3x + 3z = -3y

Add '-3z' to each side of the equation.
3x + 3z + -3z = -3y + -3z

Combine like terms: 3z + -3z = 0
3x + 0 = -3y + -3z
3x = -3y + -3z

Divide each side by '3'.
x = -1y + -1z

Simplifying
x = -1y + -1z

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