3x-(3x+5)-8=1/2(8x+20)-3x+5

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Solution for 3x-(3x+5)-8=1/2(8x+20)-3x+5 equation: 



3x-(3x+5)-8=1/2(8x+20)-3x+5

We move all terms to the left:

3x-(3x+5)-8-(1/2(8x+20)-3x+5)=0



Domain of the equation: 2(8x+20)-3x+5)!=0

x∈R



We get rid of parentheses

3x-3x-(1/2(8x+20)-3x+5)-5-8=0

We multiply all the terms by the denominator


3x*2(8x+20)-3x+5)-3x*2(8x+20)-3x+5)-(1-5*2(8x+20)-3x+5)-8*2(8x+20)-3x+5)=0

We add all the numbers together, and all the variables

-3x+3x*2(8x+20)+5)-3x*2(8x+20)-3x+5)-(1-5*2(8x+20)-3x+5)-8*2(8x+20)-3x+5)=0

Wy multiply elements

6x^2(8+5)-3x-3x*2(8x+20)-3x-5*2(8x+20)-3x+5)-8*2(8x+20)-3x+5)+5)-(1=0

We add all the numbers together, and all the variables

6x^213-3x-3x*2(8x+20)-3x-5*2(8x+20)-3x+5)-8*2(8x+20)-3x+5)+5)-(1=0

We add all the numbers together, and all the variables

6x^213-9x-3x*2(8x+20)-5*2(8x+20)+5)-8*2(8x+20)-3x+5)+5)-(1=0

Wy multiply elements

6x^213-6x^2(8-10x(8+5)-8*2(8x+20)-3x+5)-9x+5)-(1=0

We do not support expression: x^213

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