3x-(4+x2)=8

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Solution for 3x-(4+x2)=8 equation: 



3x-(4+x2)=8

We move all terms to the left:

3x-(4+x2)-(8)=0

We add all the numbers together, and all the variables

-(+x^2+4)+3x-8=0

We get rid of parentheses

-x^2+3x-4-8=0

We add all the numbers together, and all the variables

-1x^2+3x-12=0

a = -1; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·(-1)·(-12)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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